How many grams of Chromium Chloride III are needed to produce 75.0 of Silver Chloride?
CrCl3 + AgNO3 --> Cr(NO3) +AgCL

27.61g

Explanation:

First thing first, generate a balanced equation for the reaction as illustrated below:

CrCl3 + 3AgNO3 —> Cr(NO3)3 + 3AgCl

Next, we'll find the molar mass of CrCl3 and AgCl:

Molar Mass of CrCl3 = 52 + (3x35.5)

= 158.5g/mol

Molar Mass of AgCl = 108 + 35.5 = 143.5g/mol

But from the balanced equation, 3 mol of AgCl was produced. Therefore, the mass conc. of AgCl from the equation = 3 x 143.5 = 430.5g.

From the equation,

158.5g of CrCl3 produced 430.5g of AgCl.

Therefore, Xg of CrCl3 will produce 75g of AgCl i.e

Xg of CrCl3 = (158.5x75) / 430.5 =27.61g.

So, 27.61g of CrCl3 will produce 75g of AgCl