Nitrogen monoxide, NO, reacts with hydrogen, H₂, according to the following equation.

What would the rate law be if the mechanism for this reaction were as follows?
(Rate expressions take the general form: rate = k . [A]a . [B]b.)
(slow)
(fast)

Answer : The rate law for the overall reaction is,

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

As we are given the mechanism for the reaction :

Step 1 :    (slow)

Step 2 :     (fast)

Overall reaction :

The rate law expression for overall reaction should be in terms of .

As we know that the slow step is the rate determining step. So,

The slow step reaction is,

The expression of rate law for this reaction will be,

Hence, the rate law for the overall reaction is,

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;