In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two significant figures) the values of vrms for both molecules. (Eq. (20.26) relates vrms to absolute temperature.

Explanation:

Expression for the speed is as follows.

where,   = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of as follows.

                            =

                            = 498.5 m/s

Hence, for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its speed as follows.

                              =

                              = 524.5 m/s

Therefore, speed for nitrogen is 524.5 m/s.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.