Chemistry, 18.02.2020 22:31 iceecole6570
Consider the reaction 5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq) +3H2O(l) The average rate of consumption of Br− is 2.06×10−4 M/s over the first two minutes. What is the average rate of formation of Br2 during the same time interval? Express your answer with th
Answers: 3
is the average rate of formation of bromine gas during the same time interval.
![Br^-=-\frac{d[Br^-]}{dt}= 2.06\times 10^{-4} M/s](/tpl/images/0514/7541/2309f.png)
![R=\frac{-1}{5}\frac{d[Br^-]}{dt}](/tpl/images/0514/7541/8ebea.png)
![Br_2=\frac{d[Br_2]}{dt}](/tpl/images/0514/7541/0afba.png)
![R=\frac{1}{3}\frac{d[Br_2]}{dt}](/tpl/images/0514/7541/e4812.png)
![\frac{d[Br_2]}{dt}=R\times 3=4.12\times 10^{-5}M/s\times 3=1.236\times 10^{-4} M/s](/tpl/images/0514/7541/aba02.png)
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Consider the reaction 5Br−(aq)+BrO−3(aq)+6H+(aq)→3Br2(aq) +3H2O(l) The average rate of consumption o...
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