If 34.5 g of Copper reacts with 70.2 g of silver nitrate, according to the following
reaction, what is the maximum number of grams of silver that can be

Cu + _ Ag(NO3) → Cu(NO3)2 + Ag

44. 6gAg can be produced

Explanation:

Hello,

In this case, the first step is to write the balanced chemical reaction:

Next, we find the limiting reactant, for that reason we compute the moles of copper that are available and the moles that will react with 70.2 g of silver nitrate as shown below:

In such a way, since there are more available moles of copper, it is in excess, so the silver nitrate is the limiting reactant, this, the maximum grams of silver result:

Best regards.

- aluminum and copper chloride.

- the chloride ion to separate the aluminum from the oxygen so that the aluminum can react with the copper ions (and the water molecules).

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"