![[H_3O^+]=[OH^-]=10^{-7}moles/liter](/tpl/images/0516/2864/71fe6.png)
![Keq=[H_3O^+(aq)][OH^-(aq)]](/tpl/images/0516/2864/3173f.png)
![[H_3O^+(aq)]=[OH^-(aq)]](/tpl/images/0516/2864/dcbe5.png)
![[H_3O^+(aq)]\cdot [OH^-(aq)]=10^{-14}](/tpl/images/0516/2864/d1412.png)
![[H_3O^+(aq)]=[OH^-(aq)]=x\\\\x^2=10^{-14}\\\\x=\sqrt{10^{-14}}\\\\x=10^{-7}](/tpl/images/0516/2864/f8458.png)
![[H_3O^+(aq)]=[OH^-(aq)]=10^{-7}](/tpl/images/0516/2864/6704e.png)
Pure water at 25°C
ionizes in the presence of acid to form an equilibrium in which
...
Chemistry, 19.02.2020 23:25 schapethan
Pure water at 25°C
ionizes in the presence of acid to form an equilibrium in which
StartBracket upper H subscript 3 upper O superscript plus EndBracket equals StartBracket upper O upper H superscript minus EndBracket equals 10 to the 7 moles per liter.
ionizes in the presence of acid to form an equilibrium in which
StartBracket upper H subscript 3 upper O superscript plus EndBracket equals StartBracket upper O upper H superscript minus EndBracket equals 10 to the negative 7 moles per liter.
self-ionizes to form an equilibrium in which StartBracket upper H subscript 3 upper O superscript plus EndBracket equals StartBracket upper O upper H superscript minus EndBracket equals 10 to the 7 moles per liter.
self-ionizes to form an equilibrium system in which
StartBracket upper H subscript 3 upper O superscript plus EndBracket equals StartBracket upper O upper H superscript minus EndBracket equals 10 to the negative 7 moles per liter.
Answers: 1
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