If 5.00 mL of 1.00 M HCl is used to titrate the hydroxide ion produced by a piece of Sodium, What mass of Sodium is used in grams?

Explanation:

Equation of the reaction:

NaOH + HCl --> NaCl + H2O

Volume of HCl = 5 ml

Molar concentration = 1 M

Number of moles = molar concentration * volume

= 1 * 0.005

= 0.005 mol of HCl

By stoichiometry, 1 mole of HCl completely neutralizes 1 mole of NaOH

Therefore, number of moles of NaOH = 0.005 mol

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

NaOH --> Na+ + OH-

Mass = molar mass * number of moles

= 40 * 0.005

= 0.2 g of Na+

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