Study the balanced equation.

3Hg(OH)2 + 2H3PO4 → Hg3(PO4)2 + 6H2O

How many mols of phosphoric acid (H3PO4) reacted to form 3.13 x 101 mol of water (H2O)?

A) 5.22 × 100 mol H3PO4
B) 9.39 × 101 mol H3PO4
C) 6.26 × 101 mol H3PO4
D) 1.04 × 101 mol H3PO4

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

answeridentity;

the correct answer would be b) volume versus temperature, because they are also directly proportional.