The reaction 2A → A2 was experimentally determined to be second order with a rate constant, k, equal to 0.0265 M–1min–1. If the initial concentration of A was 2.00 M, what was the concentration of A (in M) after 180.0 min?

0.19M

Explanation:

2A → A2

Rate constant = 0.0265 M–1min–1

Initial concentration = 2.00 M

Final Concentration = ?

time, t =  180min

The formular relating the parameters is given as;

1 / [A] = kt + 1 / [A]o

1 / [A] = 0.0265 * 180 + (1 / 2)

1 / [A] = 4.77 + 0.5

[A] = 1 / 5.27 = 0.19M

0.88m hope i am correct : )