For an enzymatically catalyzed reaction in which the measured values for KM and Vmax are, respectively, 10.0 mM and 0.172 mM min-1, what is the value of the turnover number? The concentration of enzyme used in the reaction is 10.0 μM.

17.2 minutes is the value of the turnover number.

Explanation:

Using Michaelis-Menten equation:

Where  :

= max rate velocity

[S] = substrate concentration

= Michaelis-Menten constant

V = reaction rate

= catalytic rate constant

= initial enzyme concentration

We have :

is the rate is obtained when all enzyme is bonded to the substrate. is termed as the turnover number.

17.2 minutes is the value of the turnover number.

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

if you're asking what comes out, it's steam.