Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction of 480.1 g of CrO2 yields 402.4 g of Cr203. Calculate the theoretical yield of Cr203 (assuming complete reaction) and its percentage yield. Theoretical yield = Percentage yield = Submit Answer 2 question attempts remaining

The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of = 480.1 g

Molar mass of = 84 g/mol

Putting values in equation 1, we get:

For the given chemical equation:

By Stoichiometry of the reaction:

4 moles of produces 2 moles of chromium (III) oxide

So, 5.72 moles of will produce = of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

To calculate the percentage yield of chromium (III) oxide, we use the equation:

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

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