Find the final temperature of the mixture, if two cup of water having masses of
150g and 250g and temperatures T1= 30 °C and T2=75 °C (respectively) are mixed
in an isolated system in which there is no heat lost.

Please help!!

The answer to your question is  Te= 58.13°C

Explanation:

Data

m1 = 150g   t1 = 30°C

m2 = 250g  t2 = 75°C

Te = final temperature

Equation

                    m(Te - T1) = -m(Te - T2)

Substitution

                    150(Te - 30) = -250(Te - 75)

Expand

                    150Te - 4500 = -250Te + 18750

Solve for Te

                    150Te + 250Te = 18750 + 4500

                                  400Te = 23250

                                         Te = 23250/400

                                         Te= 58.13°C

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.