What is the osmotic pressure of a solution made by dissolving 55.0 g of glucose, C6H12O6, in enough water to form 800.0 mL of solution at 10.0 ∘C ? Express your answer to three significant figures and include the appropriate units. View Available Hint(s)

The osmotic pressure is 8.85 atm

Explanation:

Step : Data given

Mass of glucose = 55.0 grams

Volume of water =800.0 mL

Temperature = 10.0 °C

Step 2: Calculate moles glucose

Moles glucose = mass glucose / molar mass glucose

Moles glucose = 55.0 grams / 180.156 g/mol

Moles glucose = 0.305 moles

Step 3: Calculate osmotic pressure

π = iMRT  

⇒ with π = the osmotic pressure = TO BE DETERMINED

⇒ with i = the van't Hoff factor for glucose = 1

⇒ with M = the concentration = moles / volume = 0.305 moles / 0.800 L =0.381 M

⇒ with R = the gas constant = 0.08206 L*atm*mol¨K

⇒ with T = the temperature = 10.0 °C = 283 K

 π = 1* 0.381 *0.08206 * 283

 π = 8.85 atm

The osmotic pressure is 8.85 atm

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