8. The rate constant for the reaction below is 6.2 x 10−5 mol L−1s−1. If the initial concentration of A is 0.0500 M, what is its concentration after 115 s?

The concentration after 115 seconds is 0.0496 M

Explanation:

Applying integrated rate law for a first-order reaction, we will have;

where;

is the concentration at a time t

is the initial concentration

k is the rate constant for the reaction

t is the given time

Given;

 = 0.05 M

k = 6.2 x 10⁻⁵ mol L⁻¹s⁻¹

t = 115 seconds

Substitute these values and solve for

Therefore, the concentration after 115 seconds is 0.0496 M

hope you got the answer