A 71.0 mL 71.0 mL aliquot of a 1.30 M 1.30 M solution is diluted to a total volume of 248 mL. 248 mL. A 124 mL 124 mL portion of that solution is diluted by adding 133 mL 133 mL of water. What is the final concentration? Assume the volumes are additive.

The answr to the question is

The final concentration = 0.179 M

Explanation:

To solve the question, we note the dilution factor as follows

The dilution factor is given by

Therefore we have, for the first dilution

71 mL of 1.3 M diluted to 248 mL which gives

= 1.3×71/248 = 0.372 M

to the 124 mL portion of the diluted solution 133 mL of water is added thus we have 124 +133 =257 mL

We therrefore proceed as folows

where = concentration of new solution

= 0.372 M

= 124 mL

= 257 mL

Therefore   = 0.372×124/257 = 0.179 M

The final concentration = 0.179 M

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.