N2H4 + N2O4 --> N2 + H2O

1. What is the limiting reagent?
2. How many grams of H2O is produced?

Explanation:

Since this problem is incomplete, let us give a simple explanation to solve it.

In any reaction, we always have reactants that are in short supply and those that are in excess.

A reactant in short supply in a reaction is called the limiting reagent. This reactant will usually determine the extent of the reaction. When it is used up, the reaction will stop and will not proceed further.

To solve for the limiting reagent, convert the given mass to number of moles. Always work with number of moles.

Then write the balanced reaction equation.

Compare the moles from the balanced equation to that obtained. The reacting specie that is lesser in proportion is the limiting reagent

To solve the second part;

   Compare the number of moles of the limiting reactant to that of the product i.e H₂O;

Use this number of moles to find mass;

         Mass of H₂O = number of moles x molar mass

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.