Given the chemical equation: Fe2O3 + 3CO --> 2Fe + 3CO2

You need to make 112 g of iron (Fe). You have as much carbon monoxide (CO) as needed. How much iron oxide (Fe2O3) do you need to start with?

The answer to your question is 160 g of Fe₂O₃  

Explanation:

Data

mass of Fe = 112 g

mass of CO = in excess

mass of Fe₂O₃ = ?

Balanced chemical reaction

                Fe₂O₃  +  3CO  ⇒  2Fe  +  3CO₂

Process

1.- Calculate the molar mass of Fe₂O₃ and Fe

Molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 112 + 48 = 160 g

atomic mass of Fe = 56

2.- Use proportions to calculate the mass of Fe₂O₃ needed

                160 g of Fe₂O₃ 2(56) g of Fe

                 x     g of Fe₂O₃ 112 g of Fe

                 x = (112 x 160) / 2(56)

                 x = 17920/112

                 x = 160 g of Fe₂O₃          

answer: i would say b.

explanation: