Given the chemical equation: Fe2O3 + 3CO --> 2Fe + 3CO2
You need to make 112 g of iron (Fe). You have as much carbon monoxide (CO) as needed. How much iron oxide (Fe2O3) do you need to start with?

Question 3 options:

1 mole Fe2O3

2 moles Fe2O3

4 moles Fe2O3

56 moles Fe2O3

1 mole

Explanation:

m(Fe) = 112 g

n(Fe₂O₃) = ?

First you must calculate how many moles of Fe is in 112 g of Fe:

n(Fe) = m(Fe) / Ar(Fe) = 112 g / 55,85 g moles⁻¹ = 2 moles

Now, from reaction you compare moles of Fe and Fe₂O₃ :

2 n(Fe₂O₃) =  n(Fe)

n(Fe₂O₃) = n(Fe) / 2 = 1 mole

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