What is the specific heat of an unknown metal if 1.67 kcal of energy are required to raise the temperature of 79.2 g sample of the metal by 63.3 degrees celsius

The answer to your question is       C = 0.000333 kcal/g°C

or  C = 0.333 cal/g°C

Explanation:

Data

 Q = 1.67 kcal

 mass = 79.2 g

 ΔT = 63.3°C

Formula

 Q = mCΔT

Solve for C

 C = Q/mΔT

Substitution

  C = 1.67/(79.2 x 63.3)

Simplification

   C = 1.67 / 5013.4

Result

    C = 0.000333 kcal/g°C

or  C = 0.333 cal/g°C

The specific heat of the unknown metal is 0.333 cal/g°C

Explanation:

Step 1: Data given

1.67 kcal of energy is required

Mass of the metal = 79.2 grams

Temperature rise = 63.3 °C

Step 2: Calculate specific heat of the metal

Q = m*c*ΔT

⇒ with Q = the energy required = 1.67 kcal = 1670 cal

⇒ with m = the mass of the metal = 79.2 grams

⇒ with c = the specific heat of the metal = TO BE DETERMINED

⇒ with ΔT = the temperature rise = 63.3 °C

1670 cal = 79.2 grams * c * 63.3 °C

c = 0.333 cal/g*°C

The specific heat of the unknown metal is 0.333 cal/g°C

well in order to answer this question you have to provide more information < 3

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.