Chemistry, 24.02.2020 18:29 OkayLearn5522

N2 + 18n + 81 need help

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Answer from: ayoismeisalex

(n + 9)^2

Explanation:

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring n2+18n+81

The first term is, n2 its coefficient is 1 .

The middle term is, +18n its coefficient is 18 .

The last term, "the constant", is +81

Step-1 : Multiply the coefficient of the first term by the constant 1 • 81 = 81

Step-2 : Find two factors of 81 whose sum equals the coefficient of the middle term, which is 18 .

-81 + -1 = -82

-27 + -3 = -30

-9 + -9 = -18

-3 + -27 = -30

-1 + -81 = -82

1 + 81 = 82

3 + 27 = 30

9 + 9 = 18 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 9 and 9

n2 + 9n + 9n + 81

Step-4 : Add up the first 2 terms, pulling out like factors :

n • (n+9)

Add up the last 2 terms, pulling out common factors :

9 • (n+9)

Step-5 : Add up the four terms of step 4 :

(n+9) • (n+9)

Which is the desired factorization

Multiplying Exponential Expressions :

1.2 Multiply (n+9) by (n+9)

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is (n+9) and the exponents are :

1 , as (n+9) is the same number as (n+9)1

and 1 , as (n+9) is the same number as (n+9)1

The product is therefore, (n+9)(1+1) = (n+9)2

Final result :

(n + 9)^2

Processing ends successfully

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Answer from: Quest

For cyclohexane compounds drawn in a chair conformation: -axial bonds are vertical -equatorial bonds are parallel to two bonds within the ring. thus, as i assume the chair conformation is drawn: -the x group is in an axial position, as are the five other vertical bonds. -three axial bonds are on the top face of the ring -the other three axial bonds are on the bottom face the position of the second substituent on each ring carbon is equatorial. gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other. drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1. click this link and watch some academic videos that may you more understand the topic

Answer from: Quest

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