Calculate ΔH for the following reaction: N2 + 3H2 → 2NH3. Average Bond Energies N≡N, 941 kJ/mol H–H, 432 kJ/mol N–H, 391 kJ/mol HOW DO WE GET THERE? What is the total energy required to break the reactant bonds (in both N2 and H2)? Total energy required = kJ