Assuming gasoline is isooctane, with a density of g/mL, what is the theoretical yield of carbon dioxide produced by the combustion of gal of gasoline (the approximate annual consumption of gasoline in the United States)?

This is an incomplete question, here is a complete question.

Assuming gasoline is 89.0% isooctane, with a density of 0.692 g/mL, what is the theoretical yield (in grams) of CO₂ produced by the combustion of 1.80 × 10¹⁰ gallons of gasoline (the estimated annual consumption of gasoline in the U.S.)?

Answer : The theoretical yield of carbon dioxide is

Explanation :  Given,

Volume of isooctane =

First we have to convert volume into liters, we use the conversion factor:

1 gallon = 3.785 L

So,

Now we have to calculate the mass of isooctane.

Volume of isooctane =    (Conversion factor:  1 L = 1000 mL)

Density of isooctane = 0.692 g/mL

Now put all the given values in above equation, we get:

Now we have to calculate the number of moles.

     .....(1)

Given mass of isooctane =

Molar mass of isooctane = 114.22 g/mol

Now put all the given values in equation 1, we get:

The chemical equation for the combustion of isooctane is:

By Stoichiometry of the reaction we can say that,

As, 2 moles of isooctane produces 16 moles of carbon dioxide.

So, of isooctane will produce = of carbon dioxide

Now we have to calculate the mass of carbon dioxide.

Molar mass of carbon dioxide = 44.00 g/mol

Moles of carbon dioxide =

Now put all the given values in equation 1, we get:

Hence, the theoretical yield of carbon dioxide is

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.

c) should be the answer.