Chemistry, 25.02.2020 00:04 andreanb8083

According to the following reaction, what mass of PbCl2 can form from 235 mL of 0.110 M KCl solution? Assume that there is excess Pb(NO3)2. 2 KCl(aq) + Pb(NO3)2(aq) → PbCl2(s) + 2 KNO3(aq)

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According to the following reaction, what mass of PbCl2 can form from 235 mL of 0.110 M KCl solution...

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