Consider the following mechanism for the reaction between t-butyl chloride and water: (CH_3)_3 CCl(aq) rightarrow (CH_3)_3 C^+ (aq) + Cl^- (aq) (CH_3)_3 C^+ (aq) + H_2O(l) rightarrow (CH_3)_3 CHOH^+ (aq) (CH_3)_3 CHOH^+ (aq) + H_2O(l) rightarrow (CH_3)_3 COH(aq) + H_3 O^+ (aq) Write the chemical equation of the overall reaction: Are there any intermediates in this mechanism? yes no If there are intermediates, write down their chemical formulas. Put a comma between each chemical formula, if there's more than one.

The correct answer is b.hoped i you

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.