A student was trying to determine the mole percent of A in a mixture of A and B using refractive index. If their mixture has a refractive index of 1.5248 and pure A and pure B each had refractive indices of 1.7058 and 1.3658, respectively, what was the mole percent of A in their mixture. Type your numerical answer rounded to the 3rd decimal place (i. e. 45.982 or 9.550, etc) without a percent sign.

Explanation:

Formula to calculate refractive index of n is as follows.

     n =

where,     = mole fraction of A

              = mole fraction of B

              = refractive index of A

              = refractive index of B

Hence, putting the given values into the above formula as follows.

         n =

         1.5248 = ........ (1)

Also, it is known that = 1

and,           ......... (2)

Now, put equation (2) in equation (1) as follows.

        1.5248 =  

        1.5248 =  

          = 0.467

And, the value of   is calculated as follows.

                       =

                       = 0.533

Hence, mole percentage of A will be calculated as follows.

      Mole % of A =      

                            =

                            = 46.7%

Thus, we can conclude that the mole percent of A in their mixture is 46.7%.

anaphase.

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