The reaction of sulfuric acid (H2SO4) with potassium hydroxide (KOH) is described by the equation below. Suppose
0.06 L of KOH with unknown concentration is placed in a flask with bromthymol blue indicator. A solution of 0.20 M
H2504 is dripped into the KOH solution. After exactly 0.017 L of H2SO4 is added, the Indicator changes from blue to
yellow. What is the concentration of the KOH? You must show all of your work to earn credit. (4 points)
H2SO4 + 2KOH → K2SO4 + 2H20
Answers: 2
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The reaction of sulfuric acid (H2SO4) with potassium hydroxide (KOH) is described by the equation be...
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