A cannonball was launched by a cannon. The function H(t)=−t2+100t+100 describes the position of the cannonball t seconds after it was launched and the height H is in metres. How long did it take for the cannonball to reach its maximum height?

The answer to your question is t = 50 s

Explanation:

Data

Function

H(t) = -t² + 100t + 100

Process

1.- Find the derivative of the function to get the maximum

H'(t) = -2t + 100

2.- Equal to zero the derivative

          -2t + 100 = 0

3.- Solve for t

          -2t = -100

             t = -100/-2

             t = 50 s

4.- Conclusion

It takes 50 s to reach the maximum height

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

answer; talc and gypsum;