Write the balanced net ionic equation for a solution formed from CaCl2(aq) and Na2SO4 (aq)

Ca^2+(aq) + SO4^2-(aq) → CaSO4(s)

Explanation:

Step 1: The unbalanced equation

CaCl2(aq) + Na2SO4 (aq) → ...

Step 2: Balancing the equation

CaCl2(aq) + Na2SO4 (aq) → CaSO4 + NaCl

On the left side we have 2 times Cl (in CaCl2), On the right side we have 1 time Cl (in NaCl)

On the left side we have 2 times Na (in Na2SO4), on the right side we have 1 time Na (in NaCl)

To balanced the amount of Na and Cl we have to multiply NaCl, on the right side, by 2. Now the equation is balanced.

CaCl2(aq) + Na2SO4 (aq) → CaSO4(s) + 2NaCl(aq)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Ca^2+(aq) + SO4^2-(aq) → CaSO4(s)

sure what is it? ^w^

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."