A sample of nitrogen gas occupies a volume of 2.55 L when it is at 755 mm Hg and 23 degrees Celsius. Use this information to determine the moles of nitrogen gas present. Volume is increased to 4.10 L and temperature is decreased to 18 degrees Celsius. Calculate the final pressure

The final pressure is 461.6 mm Hg

Explanation:

Step 1:Data given

Volume of N2 = 2.55L

Pressure N2 = 755 mm Hg

Temperature = 23.0 °C

New volume = 4.10 L

Temperature = 18.0 °C

Step 2: Calculate the fina pressure

P1V1/T1 = P2V2/T2

P2 = P1V1/T1 * T2/V2

⇒ with P1 = initial pressure = 755/760 atm =0.993421 atm

⇒ with V1 = the initial volume = 2.55L

⇒ with T1 = the initial temperature = 23.0 °C = 296 K

⇒ with P2 = The final pressure

⇒with V2 = the new volume = 4.10 L

⇒with T2 = the new temperature = 18.0 °C = 291 K

P2 = 755 mm *2.55 L *296K/(291 K* 4.10 L) = 461.6 mm Hg

The final pressure is 461.6 mm Hg

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.

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