An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the pH of the solution is 8.08. Part A What is the identity of the salt?

The unknown salt is NaF

Explanation:

To calculate the molarity of solution, we use the equation:

Moles of salt = 0.050 moles

Volume of solution = 0.500 L

Putting values in above equation, we get:

pH + pOH = 14

We are given:

pH = 8.08

Putting values in above equation, we get:

The unknown salt given are formed by the combination of weak acid and strong acid which is NaOH

The chemical equation for the hydrolysis of ions follows:

Initial:              0.1

At eqllm:        0.1-x                           x              x

Concentration of

The expression of for above equation follows:

Putting values in above expression, we get:

where,

= Ionic product of water =

= Acid dissociation constant

= Base dissociation constant =

Putting values in above equation, we get:

We know that:

So, the calculated is approximately equal to the of HF

Hence, the unknown salt is NaF

first one is the correct answer

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i