Compute the boiling point elevation of a salt water solution that contains 3.80 g of NaCl dissolved in 122 mL of water. Enter the number of degrees celsius that the boiling point will be elevated.

The boiling point elevation of salt water solution is 0.55°C

Explanation:

To calculate the mass of water, we use the equation:

Density of water = 1 g/mL

Volume of water = 122 mL

Putting values in above equation, we get:

To calculate the elevation in boiling point, we use the equation:

Or,

where,

= ?

i = Vant hoff factor = 2 (For NaCl)

= molal boiling point elevation constant = 0.52°C/m.g

= Given mass of solute (NaCl) = 3.80 g

= Molar mass of solute (NaCl) = 58.55 g/mol

= Mass of solvent (water) = 122 g

Putting values in above equation, we get:

Hence, the boiling point elevation of salt water solution is 0.55°C

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer