Identify the limiting reactant when 7.81 g of HCl reacts with 5.24 g of NaOH to produce NaCl and H2O

NaOH is limiting

Explanation:

                                 Hcl   +    NaOH        Nacl   + H2O  

Given                     7.81g        5.24g

mol weights           1+35.5     23+16+1

                                 36.5            40

No of Moles        7.81/36.5       5.24/40  

                             0.2139              0.131

No of moles = weight/ molecular weight

No of moles of NaOH is  lower so it is limiting as according to equation one mole of Hcl requires mole of NaOH so equal number of moles are required. NaOH is 0.131 which is far lower than 0.2139

represents arrow in forward direction in equation

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

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