Chemistry, 26.02.2020 16:59 valtrump3256
7) For the reaction 9A (g) + B (g) 5C(g) + 1/6 D (g), it takes 4 and a half minutes for the concentration of C to increase to 1.33 M. What would be the decrease in A during this time interval? a. 0.27 b. 0.044 c. 0.53
Answers: 3
![\text{Rate of disappearance of }A=-\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}](/tpl/images/0524/9437/d9f99.png)
![\text{Rate of formation of }C=+\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}](/tpl/images/0524/9437/0b475.png)
= change in concentration of C = 1.33 M
= change in time = 4.5 min![\frac{1}{9}\times \frac{\Delta [A]}{\Delta t}=\frac{1}{5}\times \frac{\Delta [C]}{\Delta t}](/tpl/images/0524/9437/4b36e.png)
![\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{\Delta [C]}{\Delta t}](/tpl/images/0524/9437/d1e06.png)
![\frac{\Delta [A]}{\Delta t}=\frac{9}{5}\times \frac{1.33M}{4.5min}](/tpl/images/0524/9437/041b7.png)
![\frac{\Delta [A]}{\Delta t}=0.53M/min](/tpl/images/0524/9437/813ba.png)
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7) For the reaction 9A (g) + B (g) 5C(g) + 1/6 D (g), it takes 4 and a half minutes for the concen...
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