N2+3H2—> 2NH3 What volume of NH3 at STP is produced if 25.0g of N2 is reacted with an excess of H2 ?

The answer to your question is 40 L of NH₃

Explanation:

Data

Volume of NH₃ = x

mass of N₂ = 25 g

mass of H₂ = excess

Balanced chemical reaction

                     N₂  +  3H₂   ⇒  2NH₃

Process

1.- Find the molar mass of N₂ and NH₃

N₂ = 14 x 2 = 28g

2NH₃ = 2[ 14 + 3] = 34 g

2.- Write a proportion to solve this problem

                    28 g of N₂ 34 g of NH₃

                     25 g of N₂   x

                     x = (25 x 34)/28

                     x = 30.36 g of NH₃

3.- Calculate the volume of NH₃

                     17 g of NH₃ 22.4 L

                     30.36 g of NH₃  x

                     x = (30.36 x 22.4) / 17

                     x = 40 L

i believe the answer is a.