In a bomb calorimeter compartment surrounded by 1.144 kg of water, the combustion of 1.081 g of benzene, C6H6 (l), raised the temperature of the water from 23.640°C to 32.692°C. The heat capacity of the calorimeter is 0.852 kJ/°C. What is ∆E for the reaction in kJ/mol of C6H6 (l), the specific heat of water is 4.184 J/g°C. Enter the correct sign (+ or -). Enter to 0 decimal places.

Icant see the pictures 

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

Sorry i dont understand the question can you rephase it?

Answer : option a) 84explanation :

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.