Consider the reaction 2X2Y+Z2⇌2X2YZ which has a rate law of rate= k[X2Y][Z2] Select a possible mechanism for the reaction. View Available Hint(s) Consider the reaction which has a rate law of Select a possible mechanism for the reaction. A Step1:Step2:Step3:Z2→Z+Z (slow)X2Y+Z→X2YZ (fast) X2Y+Z→X2YZ (fast) B Step1:Step2:X2Y+Z2→X2YZ+Z (slow)X2Y+Z→X2YZ (fast) C Step1:Step2:X2Y+Z2→X2YZ2 (slow)X2YZ2→X2YZ+Z (fast) D Step1:Step2:2X2Y⇌X4Y2 (fast)X4Y2+Z2→2X2YZ (slow) E Step1:2X2Y+Z2→2X2YZ (slow)

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.