You have 116.8 mL of a 2.50 M solution of Na2CrO4(aq). You also have 125.0 mL of a 2.50 M solution of AgNO3(aq). Calculate the concentration of Na after the two solutions are mixed together.

0.584 moles of Na+

Explanation:

The balanced reaction equation of the reaction:

Na2CrO4(aq) + 2AgNO3(aq) > 2NaNO3(aq) + AgCrO4(aq)

Na2CrO4(aq) <> 2Na+(aq) + CrO42-aq)

Amount of Na2CrO4 reacted= concentration × volume in litres

= 2.50 × 116.8/1000= 0.292 moles

Concentration of Na2+ present = 2×0.292= 0.584 moles

From the balanced reaction equation; the product also contains 0.584 moles of Na+