The reaction rate constant for a particular second order reaction is 0.47 L/mol sec. If the initial concentration of reactant is .25 mol/L, how many seconds will it take for the concentration to decrease to .13 mol/L

7.9 s

Explanation:

Given data

Let's consider the concentration-time equation for a second-order reaction.

1/[A] = 1/[A]₀ + k.t

1/[A] - 1/[A]₀ = + k.t

t = 1/[A] - 1/[A]₀ / k

t = 1/0.13 M - 1/0.25 M / 0.47 L/mol.s

t = 7.9 s

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