A 15 meter by 12 meter pool of water has a depth of 2.2 meters. What mass of silver ion is present in the pool if the concentration of silver ion is 0.14 ppm? (1 m3 = 1000 L; assume the density of the solution is 1.00 g/mL

there is 55.44 gr of silver ion in the pool

Explanation:

assuming that the pool has an rectangular area , the volume covered by the pool is

volume of pool = area*depth = 15m* 12m * 2.2 m = 396 m³

assuming that all the pool is covered with the solution that has the silver ion , then

mass = concentration in ppm * density of solution * volume of pool = 0.14*10⁻⁶ gr of silver/gr of solution * 1 gr of solution/1 ml * 396 m³ * 10⁶L/m³ = 0.14*396 gr = 55.44 gr

therefore there is 55.44 gr of silver ion in the pool