At a certain temperature, 0.800 mol SO 3 is placed in a 1.50 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equilibrium, 0.150 mol O 2 is present. Calculate K c .

Answer : The value of equilibrium constant (K) is, 0.004

Explanation :

First we have to calculate the concentration of

and,

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

Initial conc.       1.2             0               0

At eqm.          (1.2-2x)        2x               x

As we are given:

Concentration of at equilibrium = x = 0.1 M

The expression for equilibrium constant is:

Now put all the given values in this expression, we get:

Thus, the value of equilibrium constant (K) is, 0.004

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.