Dilute solutions of NaHCO3 are sometimes used in treating acid burns.

How many milliliters of 0.100 M NaHCO3 solution are needed to prepare 750.0 mL of 0.0500 M NaHCO3 solution?

We need 375 milliliters of 0.100 M NaHCO3 solution

Explanation:

Step 1: Data given

Initial molarity NaHCO3 = 0.100 M

Volume prepared solution = 750.0 mL

Molarity prepared solution = 0.05 M

Step 2: Calculate initial volume

C1*V1 = C2V2

⇒with C1 = the initial concentration = 0.100 M

⇒with V1 = The initial volume = TO BE DETERMINED

⇒with C2 = the new concentration = 0.0500M

⇒with v2 = the new volume = 750.0 mL = 0.750 L

0.100 M * V1 = 0.0500 M * 0.750 L

V1 = (0.0500M * 0.750L)/0.100 M

V1 = 0.375 L = 375 mL

We need 375 milliliters of 0.100 M NaHCO3 solution

the solar system used to have much dust particles option no d