What is the specific heat of a 42.6 gram compound that changes from 12 Celsius to 46 Celsius when it absorbs 1260 KJ of energy

869.93J/g°C

Explanation:

From the question given, we obtained the following:

M = 42.6g

T1 = 12°C

T2 = 46°C

ΔT = T2 — T1 = 46 — 12 = 34°C

C =?

Q = 1260 KJ = 1260000J

Q = MCΔT

C = Q / MΔT

C = 1260000 /(42.6 x 34)

C = 869.93J/g°C

Therefore, the specific heat capacity is 869.93J/g°C

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8