What is the molarity of a solution that contains 40. grams of NaOH in 0.50 liter of solution

The molarity of the solution is: 2 M

Explanation:

We calculate the weight of 1 mol of NaOH:

Weight 1 mol NaOH= Weight Na + Weight 0 + Weight H= 23 g+16g+ 1 g= 40g/mol

The molarity is the quantity of moles in 1000ml (1 liter) of solution:

0,5liter40 grams NaOH

1 literx=(1 liter x 40 grams NOH)/0,5 liter = 80 grams NaOH

40 grams1 mol NaOH

80 gramsX=(80 grams x 1 mol NaOH)/40 grams= 2 mol NaOH--> 2M

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.