How much H2 gas at STP Can be produced by the reaction . of 3.00g of Na and excess water ?

1.46L

Explanation:

2Na + 2H2O —> H2 + 2NaOH

Molar Mass of Na = 23g/mol

Mass of Na from the question = 3g

Number of mole of Na = Mass /Molar Mass

Number of mole of Na = 3/23

Number of mole of Na = 0.130mol

From the equation,

2moles of Na produced 1mole of H2.

Therefore, 0.130mol of Na will produce = 0.130/2 = 0.065mol of H2.

Recall: 1mole of a gas occupy 22.4L at stp.

If 1 mole of H2 occupy 22.4L at stp,

Then 0.065mol of H2 will occupy = 0.065 x 22.4 = 1.46L

i believe it is c.) 1575 j.