A solution with a total volume of 1000.0 mL contains 37.1 g Mg(NO3)2. If you remove 20.0 mL of this solution and then dilute this 20.0 mL sample with water until the new volume equals 500.0 mL, what is the concentration of Mg 2 ion in the 500.0 mL of solution?

0.01023 M  is the concentration of Mg 2 ion in the 500.0 mL of solution.

Explanation:

Mass of magnesium nitrate = 37.1 g

Moles of magnesium nitrate =

Volume of the solution = 1000.0 mL = 1.0 L ( 1000 mL = 1 L)

Molarity of the solution =

Molarity of the magnesium nitrate solution before dilution =

Volume of the magnesium nitrate solution before dilution =

Molarity of the magnesium nitrate solution after dilution =

Volume of the magnesium nitrate solution after dilution =

(dilution )

Molarity of the magnesium nitrate solution after dilution is 0.01023 M.

1 mole of magnesium nitrate gives 1 mole of magnesium ions.Then in 0.01023 M solution of magnesium nitrate;

0.01023 M  is the concentration of Mg 2 ion in the 500.0 mL of solution.

i think so it’s will be b yes i believe its

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.