Calculate the mass of the elements in 30.5 grams of aluminum sulfite

The molar mass of Aluminium sulphite Al2(SO3)3.

Explanation:

To calculate the mass of the Aluminium Sulphite Al2(SO3)3

 Two aluminium atoms: 2(26.98) + (32.07 + 48.00) 3

                                    = 53.96 + (80.07) 3

                                     =294.17 g/mol

 1 mole = 6.022*10²³ particles

The mass of the element (m) = M * n

                                               = 294.17 * 30.5

                                               = 8,972.18 g

Thus the mass of the element in 30.5 grms of Aluminium sulphite is 8.972g.

they are made of gases.

they have a spherical shape.

they make energy through fusion.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml