35.0 ml of acid with an unknown concentration is titrated with 24.6 ml of 0.432 m base
what is the concentration of the acid? assume the acid contributes 1 mole of (h+) ions/mole of acid and the base contributes 1 mole of (oh-) ions/mole of base.
3.29 m
0.615 m
0.304 m

We are given with the titration volume and concentration of the titrant  which is 24.6 mL of 0.432 M base. Given there is a one is to one ratio between the acid and the base, the equation becomes 26.4 ml (0.432 M) = 35 ml *(M) where M is the molarity of the acid. The concentration is 0.304 M.

The answer is b on plato.