Chemistry, 28.02.2020 19:21 semajac11135

The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.13 M, it takes min for it to decrease to 0.085 M. The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.13 M, it takes min for it to decrease to 0.085 M. 10. 11 7.0 12 8.0

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Answer from: addisonrausch

The time taken is 8 minutes.

The rate of decay of a radioactive substance is given by:

$-\frac{dN}{dt}=$ λN

here N is the concentraion, λ is the decay constant. If inially the concentration is $N_{0}$ t time t = 0.

Then solving the above equation we get:

λ = $\frac{2.303}{t}log\frac{N_{0} }{N}$

Now the half-life is defined as the time after which half of the initial concentration is left. The relation between half-life and decay constant is:

λ = $\frac{0.693}{t_{\frac{1}{2} }}$

Given that $t_{\frac{1}{2} }$ = 13 min

λ = 0.693/13 = 0.0533

So, the time taken for a first-order reaction such that the concentration decreases from 0.13 M to 0.085M can be calculated by following equation:

λ = $\frac{2.303}{t}log\frac{N_{0} }{N}$

t = $\frac{2.303}{0.0533}log\frac{0.13 }{0.085}$

t = 8 min

Learn more about radioactivity:

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Answer from: xocamiryn6584

Therefore it takes 8.0 mins for it to decrease to 0.085 M

Explanation:

First order reaction: The rate of reaction is proportional to the concentration of reactant of power one is called first order reaction.

A→ product

Let the concentration of A = [A]

$\textrm{rate of reaction}=-\frac{d[A]}{dt} =k[A]$

$k=\frac{2.303}{t} log\frac{[A_0]}{[A]}$

[A₀] = initial concentration

[A]= final concentration

t= time

k= rate constant

Half life: Half life is time to reduce the concentration of reactant of its half.

$t_{\frac{1}{2} }=\frac{0.693}{k}$

Here $t_{\frac{1}{2} }=0.13 min$

$k=\frac{0.693}{t_{\frac{1}{2}} }$

$\Rightarrow k=\frac{0.693}{13 }$

To find the time takes for it to decrease to 0.085 we use the below equation

$k=\frac{2.303}{t} log\frac{[A_0]}{[A]}$

$\Rightarrow t=\frac{2.303}{k} log\frac{[A_0]}{[A]}$

Here , $k=\frac{0.693}{13 }$ , [A₀] = 0.13 m and [ A] = 0.085 M

$t=\frac{2.303}{\frac{0.693}{13} } log(\frac{0.13}{0.085})$

$\Rightarrow t= 7.97\approx 8.0$

Therefore it takes 8.0 mins for it to decrease to 0.085 M

Answer from: Quest

If the water vapor content stays the same and the temperature drops, then the relative humidity increases. its vise versa.if the water vapor content stats the same and the temperature rises, the relative humidity decreases. so, yes, i'd say that temperature and humidity have a strong relationship.

Answer from: Quest

answer: $2c_5h_5+1fe\rightarrow 1fe(c_5h_5)_2$

the reaction is type of combination reaction.

explanation:

$? c_5h_5+? fe\rightarrow ? fe(c_5h_5)_2$

on the product side, there are 2 molecules of $c_5h_5$ bonded to fe which means one atom of fe are combined two molecules of $c_5h_5$ . so, balanced chemical equation becomes :

$2c_5h_5+1fe\rightarrow 1fe(c_5h_5)_2$

this reaction follows the reaction type of combination reaction. a combination reaction is defined as chemical reaction in which reactants combines together to form a single product.

$a+b\rightarrow ab$

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