For the reaction 3 C 2H 2( g) → C 6H 6( l) at 25°C, the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K. Calculate the standard free energy change at 25°C

The standard free energy change is -502.86 KJ

Explanation:

ΔG° = H° -TΔS°

where;

ΔG° is the standard free energy

H° is the standard enthalpy change = -631 kJ

ΔS° is the standard change in entropy = -430 J/K

T is the temperature of the system = 25⁰C = 298 K

Applying the formula above;

ΔG° = -631 kJ - ( -0.43J/K × 298K)

      = -631 kJ + 128.14 KJ

      = -502.86 KJ

Therefore, the standard free energy change is -502.86 KJ

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.