A certain radioactive isotope has a half-life of 5 days. If one is to make a table showing the half-life decay of a sample of this isotope from from 32 grams to a 1 gram

It will take 25 days for this substance to become 1gram from 32 grams.

Radioactivity or radioactive decay is the process of formation of different element from one Radioactive element due to decay of the radioactive nucleus. The radioactive decay is a first order kinetic reaction. This reaction has a straight log C vs T graph.

Here in this particular reaction, the half life of the radioactive substance is 5 days. So within 5 days, the concentration of the substance becomes halved.

Now, in the sample the amount of substance present = 32 grams

The final amount of this sample = 1 grams.

So number of half lives needed for this decay = 5 half lives.

So number of days required for this decay = =25.

So within 25 days, 32 grams of the substance becomes 1grams.

the mass of the cathode increases because ions from the solution get reduced to atoms and become part of the cathode.

explanation:

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answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.